t=-16t^2+96t+640

Solution for t=-16t^2+96t+640 equation:

t=-16t^2+96t+640

We move all terms to the left:

t-(-16t^2+96t+640)=0

We get rid of parentheses

16t^2-96t+t-640=0

We add all the numbers together, and all the variables

16t^2-95t-640=0

a = 16; b = -95; c = -640;
Δ = b2-4ac
Δ = -952-4·16·(-640)
Δ = 49985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-95)-\sqrt{49985}}{2*16}=\frac{95-\sqrt{49985}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-95)+\sqrt{49985}}{2*16}=\frac{95+\sqrt{49985}}{32}
$